Molar and molecular weight of BaMn2O8

• Molecular formula: BaMn2O8 or Ba(MnO4)2
• Relative molecular weight of BaMn2O8: 375.19829
• Molar mass of BaMn2O8: 375.19829 g/mol (0.3752 kg/mol)

Calculation of the relative molecular and molar mass of BaMn2O8

• Mr[BaMn2O8] = Ar[Ba] + Ar[Mn] * 2 + Ar[O] * 8 = 137.327 + 54.938045 * 2 + 15.9994 * 8 = 375.19829
• Molar mass (kg/mol) = Mr[BaMn2O8] : 1000 = 375.19829 : 1000 = 0.3752 kg/mol

BaMn2O8: percent composition by element

• Barium (Ba) = 137.327 : 375.19829 * 100 = 36.601 %
• Manganese (Mn) = 109.87609 : 375.19829 * 100 = 29.285 %
• Oxygen (O) = 127.9952 : 375.19829 * 100 = 34.114 %

Molar mass calculator